Loeffel-ei-loesung: Unterschied zwischen den Versionen
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<pre id="01"> | <pre id="01"> | ||
| − | + | let accY = 0 | |
| − | + | let accX = 0 | |
| − | + | let x = 2 | |
| + | let y = 2 | ||
| + | basic.forever(function () { | ||
| + | led.plot(x, y) | ||
| + | accX = input.acceleration(Dimension.X) | ||
| + | accY = input.acceleration(Dimension.Y) | ||
| + | if (accX < -150 && x > 0) { | ||
| + | x += -1 | ||
| + | } else if (accX > 150 && x < 4) { | ||
| + | x += 1 | ||
} | } | ||
| + | if (accY < -150 && y > 0) { | ||
| + | y += -1 | ||
| + | } else if (accY > 150 && y < 4) { | ||
| + | y += 1 | ||
| + | } | ||
| + | basic.pause(500) | ||
| + | basic.clearScreen() | ||
}) | }) | ||
| + | |||
</pre> | </pre> | ||
<htmlet>makecode_embed</htmlet> | <htmlet>makecode_embed</htmlet> | ||
Version vom 18. Januar 2022, 00:21 Uhr
Detailschritte
Die Lösung zu diesem Projekt wird hier in Teilen gezeigt:
- Ereignis "wenn geschüttelt"
- wenn-dann-Verzweigung
let accY = 0
let accX = 0
let x = 2
let y = 2
basic.forever(function () {
led.plot(x, y)
accX = input.acceleration(Dimension.X)
accY = input.acceleration(Dimension.Y)
if (accX < -150 && x > 0) {
x += -1
} else if (accX > 150 && x < 4) {
x += 1
}
if (accY < -150 && y > 0) {
y += -1
} else if (accY > 150 && y < 4) {
y += 1
}
basic.pause(500)
basic.clearScreen()
})
